5a
a(4a - 3)(3a - 5)
If your problem looks like this: 4a-a=_ the answer is... 3a
7a-2b
A = 6
3a - 2b
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
2a+6b
a < -12
4a+3-a =12 4a-a = 12-3 3a = 9 a = 3
4a + 3a = (4 + 3)a = 7a
idont know
It is: (a+1)(a+3) when factored