a(b + d).
Double-replacement
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
When many were taught chemistry in the 1970s this was called a double decomposition reaction. It is now called a salt metathesis reaction and also double displacement reaction. There are examples and more information at the related link.
yes because ab plus bc is ac
Commutativity.
No - a pos can not donate blood to a negative
This kind of chemical reaction is usually called "displacement" and sometimes "substitution".
Ab, Ad, Ah, AI (Abbr.), Al (Name), An, As, At, Ay (Shakespearean).
The general form for a double-displacement reaction is AB + CD -> AD + CB, where two compounds swap anions or cations to form two new compounds.
then the baby will be O plus, or AB plus , I think .
If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.
associative property