If you mean points of (-12, 3) and (0, 0) then the equation is y = -1/4x or 4y = -x
If you mean points of: (-3, 9) and (0, 0) then the equation works out as y = -3x
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel
-12
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
The given line has the equation ( y = 12x + 3 ). The slope of this line is 12. Lines that are parallel have the same slope, so the slope of any line parallel to this one is also 12.
If you mean (1, 2) and (3, 4) then its equation is y = x+1
To write the equation of a line in the form ( y = mx + b ) with a slope of ( \frac{1}{4} ) that passes through the point ( (12, 3) ), start by substituting the slope and the coordinates of the point into the equation. Plugging in ( m = \frac{1}{4} ) and the point ( (12, 3) ): [ 3 = \frac{1}{4}(12) + b ] This simplifies to: [ 3 = 3 + b ] Solving for ( b ) gives ( b = 0 ). Thus, the equation of the line is: [ y = \frac{1}{4}x ].
y=-(2/3)x + (n) where n can be any integer.
-1
8:30 7:00 to 12:00 = 5:00 12:00 to 3:30 = 3:30 Total 8:30