Write the equation of the line that passes through the points (3, -5) and (-4, -5)
gradient = (-2-5) / (2-1) = -7 hence y = -7x + C Since a point on the line is (1,5) 5 = -7 + C from which we have C = 12 The equation is y = 12 - 7x
y--6 = -3(x-4) y+6 = -3x+12 y = -3x+12-6 y = -3x+6
Points: (-2, 4) and (-6, 12) Slope: -2
I believe the slope would be: -4 / 3
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Answer this question… y = 2
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
Y=_10.35x+126.125
gradient = (-2-5) / (2-1) = -7 hence y = -7x + C Since a point on the line is (1,5) 5 = -7 + C from which we have C = 12 The equation is y = 12 - 7x
If you mean: (9, -12) then the equation is y = -12 which is a straight line parallel to the x axis passing through (0, -12)
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y=8x-12 General equation of a line Y=mx+c Y= y axis X=x axis m= gradient (how steep the line is) c= intercept (where the line crosses the y axis)
y--6 = -3(x-4) y+6 = -3x+12 y = -3x+12-6 y = -3x+6
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12