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What is the equation of the line that passes through (12) and (34)?
Wiki User
∙ 8y ago
If you mean (1, 2) and (3, 4) then its equation is y = x+1
Wiki User
∙ 8y ago
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Write the equation of the line that passes through the points 12 and 6 and 12 and -4?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
A line passes through the points 2 -2 and 1 5 find the equation of the line?
gradient = (-2-5) / (2-1) = -7 hence y = -7x + C Since a point on the line is (1,5) 5 = -7 + C from which we have C = 12 The equation is y = 12 - 7x
What is an equation of the line that passes through the poin 4 -6 and has a slope of -3?
y--6 = -3(x-4) y+6 = -3x+12 y = -3x+12-6 y = -3x+6
What is the slope of a line that passes through the points (-2 4) and (-6 12)?
Points: (-2, 4) and (-6, 12) Slope: -2
What is a slope of the line that passes through-20,-4 and -12,-10?
I believe the slope would be: -4 / 3
Write the equation of the line that passes through the points 12 and 6 and 12 and -4?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Which of the following is the equation of a line that passes through the point (12) and is parallel to the x-axis?
Answer this question… y = 2
What is the equation of the line that passes through the points (12 8) and (17 16)?
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
Which is the equation of a trend line that passes through the points (3 95) and (11 12) Round values to the nearest ten-thousandths.?
Y=_10.35x+126.125
A line passes through the points 2 -2 and 1 5 find the equation of the line?
gradient = (-2-5) / (2-1) = -7 hence y = -7x + C Since a point on the line is (1,5) 5 = -7 + C from which we have C = 12 The equation is y = 12 - 7x
What is an equation of the line 9-12 slope is 0?
If you mean: (9, -12) then the equation is y = -12 which is a straight line parallel to the x axis passing through (0, -12)
Find the slip of the line that passes through (-3, 3), (0, -12)?
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Write an equation of the line that passes through the point-4 and 1 with a slope 0f 8?
y=8x-12 General equation of a line Y=mx+c Y= y axis X=x axis m= gradient (how steep the line is) c= intercept (where the line crosses the y axis)
What is an equation of the line that passes through the poin 4 -6 and has a slope of -3?
y--6 = -3(x-4) y+6 = -3x+12 y = -3x+12-6 y = -3x+6
What is the equation of the line in point-slope form that passes through the points (-7 -10) and (-6 -8)?
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
What is the equation of the line in point slope form that passes through the points (4 8)and (2 -2)?
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
What is the equation of the line in point-slope form that passes through the points 4 8 and 2 -2?
Points: (4, 8) and (2, -2) Slope: (8--2)/(4-2) = 5 Equation: y-8 = 5(x-4) => y = 5x-12 Equation: y--2 = 5(x-2) => y = 5x-12 So straight line equation is: y = 5x-12
