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What is x when f of x equals -7 and f of x is defined to be 2x plus 8?
f(x) = 2x + 8 f(x) = -7 → 2x + 8 = -7 → 2x = -15 → x = -7½ = -7.5
What is the differential of this function Find the differential of f y equals f start parentheis x end parentheis equals 2x raised to 2 minus 3x plus 10 dy equals?
y = f(x) = 2x2 - 3x + 10dy = (4x - 3) dxNote:It's possible that the function in the question may have been f(x) = (2x)2 - 3x + 10 .If that's the case, thendy = (8x - 3) dx
If f of x equals x to the second power plus 3x minus 2 then what is f prime of x and f prime of 2?
f(x) = x2 + 3x - 2 then f'(x) = 2x + 3 and then then f'(2) = 2*2 + 3 = 4+3 = 7
Y equals -3over2x plus 1?
y = -3/2x + 1y = (-3 + 2x)/2x ory = (2x - 3)/2xWe have to deal with a rational function here f(x) = p(x)/q(x), where 2x ≠ 0, or x ≠ 0. So that the domain of f is the st of all real numbers except 0, and the y-axis (the line x = 0) is a vertical asymptote of the graph of f.Since the degree of the numerator and denominator is the same (degree 1), then the line y = 2/2 (an/bn) or y = 1, is the horizontal asymptote of the graph of f.y = (2x - 3)/2xx = 0, gives us the y-intercept, but in our case x cannot be zero, so we don't have y-intercept here.y = 0, gives us the x-intercept which is 3/2.y = (2x - 3)/2x0 = (2x - 3)/2x0 = 2x - 30 + 3 = 2x - 3 + 33 = 2x3/2 = 2x/23/2 = xSince f(-x) ≠ f(x) or -f(x), then the the graph of f has nether y-axis nor origin symmetry.y = -3/2x + 1 orf(x) = -3/2x + 1f(-x) = -3/2(-x) + 1f(-x) = 3/2x + 1-f(x) = -(-3/2x + 1)-f(x) = 3/2x - 1We can graph the function by plotting points between and beyond the x-intercept (x = 3/2) and vertical asymptote (x = 0).So we can valuate the function at -2, -1, 1, and 2.Graph the function:
Name any veritcle asympotopes of f(x)2x-3?
f(x) = 2x - 3 does not have any vertical asymptotes (nor any veritcle asympotopes).
What is the derivative of fx where fx equals 2x-3 all under square root?
f(x) = √(2x -3) f(x) = (2x - 3)^(1/2) f'(x) = (1/2)[(2x - 3)^(1/2 - 1)](2) f'(x) = (2x - 3)^(-1/2) f'(x) = 1/[(2x - 3)^(1/2)] f'(x) = 1/√(2x -3)
How do you rewrite as a function of x using function notation for 2x plus 3y equals 4?
If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
What is x when f of x equals -7 and f of x is defined to be 2x plus 8?
f(x) = 2x + 8 f(x) = -7 → 2x + 8 = -7 → 2x = -15 → x = -7½ = -7.5
What is the differential of this function Find the differential of f y equals f start parentheis x end parentheis equals 2x raised to 2 minus 3x plus 10 dy equals?
y = f(x) = 2x2 - 3x + 10dy = (4x - 3) dxNote:It's possible that the function in the question may have been f(x) = (2x)2 - 3x + 10 .If that's the case, thendy = (8x - 3) dx
If f of x equals x to the second power plus 3x minus 2 then what is f prime of x and f prime of 2?
f(x) = x2 + 3x - 2 then f'(x) = 2x + 3 and then then f'(2) = 2*2 + 3 = 4+3 = 7
If 2 f of x plus f of 4 minus x equals x squared what is f of x?
find f'(x) and f '(c)f(x) = (x^3-3x)(2x^2+3x+5
What is fx for graphing mean?
f(x) is the same thing as y= example: f(x)=2x+3 OR y=2x+3
How do i solve his algebra problem My homework is Function Notation The first problem is F 2x and what he gave us is F x 2x plus 5?
The equation F X 2X plus 5 equals 0.5. This is a algebra math problem.
Y equals -3over2x plus 1?
y = -3/2x + 1y = (-3 + 2x)/2x ory = (2x - 3)/2xWe have to deal with a rational function here f(x) = p(x)/q(x), where 2x ≠ 0, or x ≠ 0. So that the domain of f is the st of all real numbers except 0, and the y-axis (the line x = 0) is a vertical asymptote of the graph of f.Since the degree of the numerator and denominator is the same (degree 1), then the line y = 2/2 (an/bn) or y = 1, is the horizontal asymptote of the graph of f.y = (2x - 3)/2xx = 0, gives us the y-intercept, but in our case x cannot be zero, so we don't have y-intercept here.y = 0, gives us the x-intercept which is 3/2.y = (2x - 3)/2x0 = (2x - 3)/2x0 = 2x - 30 + 3 = 2x - 3 + 33 = 2x3/2 = 2x/23/2 = xSince f(-x) ≠ f(x) or -f(x), then the the graph of f has nether y-axis nor origin symmetry.y = -3/2x + 1 orf(x) = -3/2x + 1f(-x) = -3/2(-x) + 1f(-x) = 3/2x + 1-f(x) = -(-3/2x + 1)-f(x) = 3/2x - 1We can graph the function by plotting points between and beyond the x-intercept (x = 3/2) and vertical asymptote (x = 0).So we can valuate the function at -2, -1, 1, and 2.Graph the function:
F x equals -5x then f -3 equals?
-2
Name any veritcle asympotopes of f(x)2x-3?
f(x) = 2x - 3 does not have any vertical asymptotes (nor any veritcle asympotopes).
What does a function rule look like?
y = 2x + 3 is a function rule. This rule can also be written in several different ways:f(x) = 2x + 3 "f of x equals ...', or f: x -> 2x+3 "f maps x as ...".As a set of ordered pairs. Here is a set of pairs which satisfy our function, f: {(1,5), (2,7), (3, 9), (4, 11)}.A table of values, also known as a 'T chart'.A mapping diagram,, which has two oval shapes with numbers in them, and arrows joining the numbers in one oval to the numbers in the other oval.
