It is 2n^3 + 7n^2 - 13n + 3
n2 - 100 = (n + 10)(n - 10)
n squared minus six.
It is: 2n^2 -5n -42 equals (2n+7)(n-6) when factored
(n - 4)(n - 12)
2x squared minus 4
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42
No, unless "a" happens to be equal to 0, or to 1.
find the common multiple of 4 and 480 then minus 4. Answer is 1 over 3 and N squared. Your welcome i am your saviour.
-22 - -22
x = ? 42 = x squared minus x
2x squared minus 5x minus 3 factored is (2x+1)(x-3).
3x squared minus 25x minus 28
By factoring I get x-3 divided by x+3
n(2n - 1)(2n + 7)
There are no rational factors.
Assuming you meant 7n (not just 7 at the end of your question) - first... simplify the equation. Numbers raised to powers get priority - so your new sum is... 5n - 64n + 25n + n + 7n.... This simplifies to... -26n
Difficult to tell without brackets, but (n-1)*(n+1) = n^2 - 1 [in other words, n squared minus 1] is a useful algebraic identity.
3n2-8n+4 = (3n-2)(n-2) when factored
negative 2 squared
All the time