two decimal places. 5 in the tens and 1 in the hundreds.
It is 10790.
It is that there are no tenths in the decimal number
Thousands - Hundreds - Tens - One - Decimal - Tenth - Hundredth - Thousandth
To write 230 hundreds, 32 tens, and 6 ones in decimal numerals, you would first multiply 230 by 100 to get 23,000. Then, you would multiply 32 by 10 to get 320. Finally, you would add 6 to get a total of 23,000 + 320 + 6 = 23,326 in decimal numerals.
Yes.
It refers to counting in units and tens, multiples of tens (such as hundreds, thousands and so on), and fractions of tens (such as tenths, hundredths and so on).
74749
the second one .... first # = hundreds second # = tens third # = ones
800 tens. ------------------------ The tens column is two columns before the decimal point - in this case the decimal point is hiding at the end of the number and the tend column is the second digit from the right hand end. The tens column contains a 0 therefore there are no tens in 8000 8000 is eight thousands plus no hundreds plus no tens plus no ones.
You cannot round a number with a place value larger than the place value you seek to round it to. i.e. You cannot round thousands to hundreds, hundreds to tens, tens to ones, etc.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }