There is no relationship between sequences and probability.
There are factors such as genetic tendencies, age etc which favour male or female offspring so that the probability of a male offspring is not uniformally 1/2. Next, the question does not specify how many offspring in all, so the possible sequences could be [any sequence whether or not containing MMM] followed by [MMM] followed by [any sequence whether or not containing MMM]. As the sequence grows longer, the probability that somewhere in the sequence there are 3 male offspring in a row increases. For 3 offspring, the probability is 1/8 = 0.125 for 8 offspring, the probability is 107/256 = 0.418 The probabilities would need to be weighted together using the proportion of families that have 3 children, 4 children, and so on.
Assuming the coin is fair, the probability of that sequence is 1/16. The probability of three H and one T, in any order, is 1/4.
The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.
If you're talking with probability then it's the middle number of a sequence. Eg ( 2 3 4 5 6 7)- The mode is 4.
The key word that I use is causality. However, you cannot use probability to determine causality. Even if two events are highly correlated, probability theory cannot tell whether event A is caused by event B, or event B is caused by event A, or that both are caused by some third event that is not even part of the study.
1 out of 555555
If the sequence matters (you want H-H-T in that order), then . . .Probability of the first head = 0.5Probability of the second head = 0.5Probability of the tail on the 3rd toss = 0.5Probability of the correct 3-toss sequence = (0.5 x 0.5 x 0.5) = 1/8 = 0.125 = 12.5%=====================================================If the sequence doesn't matter, then the probability is higher.All the possible results of 3 tosses are:TTTTTHTHTTHHHTTHTHHHTHHHIf the sequence doesn't matter, there are 3 different ways to get 2 heads and 1 tail.The probability is3/8 = 0.375 = 37.5%
No, but it can represent the probability of such an outcome.
There are factors such as genetic tendencies, age etc which favour male or female offspring so that the probability of a male offspring is not uniformally 1/2. Next, the question does not specify how many offspring in all, so the possible sequences could be [any sequence whether or not containing MMM] followed by [MMM] followed by [any sequence whether or not containing MMM]. As the sequence grows longer, the probability that somewhere in the sequence there are 3 male offspring in a row increases. For 3 offspring, the probability is 1/8 = 0.125 for 8 offspring, the probability is 107/256 = 0.418 The probabilities would need to be weighted together using the proportion of families that have 3 children, 4 children, and so on.
Probability of the first head = 0.5Probability of the second head = 0.5Probability of the tail on the 3rd toss = 0.5Probability of the correct 3-toss sequence = (0.5 x 0.5 x 0.5) = 1/8 = 0.125 = 12.5%
Assuming the coin is fair, the probability of that sequence is 1/16. The probability of three H and one T, in any order, is 1/4.
If you toss the die often enough then the probability of getting the sequence 2-2-1 is 1: a certainty. The probability of getting the result in the first three tosses is 1/216.
Say there are n possible input sequences that is A1 to An. Coded sequence B is transmitted. At receiver end due to noise sequence R is obtained. Than we will calculate P(Ai/R) for i = 1 to n. Decoded sequence A for which the probability is maximum is decoded maximum likelihood sequence.
Since there are 2 outcomes for a coin toss, and you will toss the coin 3 times the number of outcomes are 23 or 8. Since H-T-H can occur only 1 way, the probability of the H-T-H sequence is 1/8.
The probability of achieving a higher flush in a game of poker is dependent on the number of players and the cards dealt. In general, the probability is low, as a higher flush requires having five cards of the same suit in a higher sequence than the other players.
There are no s's in a standard deck of cards, so the probability of selecting any s's, in any sequence of draws, in any strategy of replacement is exactly zero.
The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.