2+3+5+7+11 = 28
7 and 2
int sum = 0; int i; for(i = 0; i < n; ++i) { sum += i; }
18 is not a good first move. The sum of its proper factors is more than 18. Your opponent will have a three point lead. Large prime numbers are good first moves.
No prime power exists since there are no duplicate prime numbers in the prime factorization.
As a product of its prime factors: 2*2*2*5 = 40 or as 23*5 = 40
The sum of the first ( x ) even numbers can be expressed using the formula ( S = x(x + 1) ). This is derived from the fact that the ( n )-th even number is ( 2n ), so the sum of the first ( x ) even numbers is ( 2(1 + 2 + ... + x) = 2 \cdot \frac{x(x + 1)}{2} = x(x + 1) ). Thus, the formula provides a quick way to calculate the sum without needing to list all even numbers.
The sum of the first ( n ) even numbers can be calculated using the formula ( S = n(n + 1) ). This is derived from the fact that the ( n )-th even number is ( 2n ), and the sum of the first ( n ) even numbers is ( 2 + 4 + 6 + \ldots + 2n ). By factoring out 2, the sum simplifies to ( 2(1 + 2 + 3 + \ldots + n) ), which is ( 2 \times \frac{n(n + 1)}{2} = n(n + 1) ).
When you add two consecutive triangular numbers, the result is a perfect square. For example, the first two triangular numbers are 1 (T1) and 3 (T2), and their sum is 4, which is (2^2). In general, the sum of the (n)-th triangular number (T_n) and the ((n+1))-th triangular number (T_{n+1}) equals ((n+1)^2). This relationship holds for all pairs of consecutive triangular numbers.
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What is the product of th e prime factor 344
No number has that prime factorization since 4 isn't prime.
You need at least two numbers to find a GCF. The prime factorization of 99 is 3 x 3 x 11. Once you have the other one, you can compare.