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The sum of the first prime numbers is 5
Because the first prime numbers are 2 & 3.
Thus , 2 + 3 =5
The sum is 5
I hope you understand my reason for my answer.
By grade 4 th student
byeee
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What is the formula to find sum of n even numbers?
Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]
What is the Program to find sum of natural number using recursion?
#include #define NUM 100 //since prog is to be written for adding 100 naturalint main(){int i,sum=0;for(i=1;i
Code for sum of first natural numbers in python language?
For the first 5 natural numbers (integers):x = 1 + 2 + 3 + 4 + 5print xFor 'n' amount of natural numbers (Python v2 example)n = int(raw_input('Enter max integer: '))count = 0sumn = 0while count < n:sumn = sumn + 1count = count + 1print sumn
Create a program that will display the sum of all numbers from 1 up to the input number?
to print the sum of first ten numbers:- void main() {int i,sum; sum=0; while(i<=10) sum=sum+i; i=i+1; } printf("The sum is : %d",sum); }
Write a program to find the sum of squares of n natural numbers using c plus plus?
#include#includevoid main(){int sum_sqr(int n);clrscr();printf("%d",sum_sqr(5));//Sum of first 5 natural numbers' square valuesgetch();}int sum_sqr(int n){int i,sum=0;for(i=1;i
The variance of first n natural numbers is?
1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12
How do you find the mean of first n natural numbers?
The sum of the first n natural numbers is n*(n+1)/2 There are n numbers so their mean = (n+1)/2
What is the sum of the first 225 natural numbers?
Formula for sum of first natural number = n(n+1)/2 , here n=225 so, answer is 225(225+1)/2 = 25425
What is the sum of the squares of the first 20 natural numbers 1 to 20?
The sum of the first N square numbers is: N*(N+1)*(2N+1)/6 So putting N = 20 gives 2870.
What is the sum of the numbers from 1 to 100?
Sum of first n natural numbers is (n) x (n + 1)/2 Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050
What is the c plus plus program for printing sum to n natural numbers?
main() { int i, n, sum=0; cout<<"Enter the limit"; cin>>n; for(i=0;i<=n;i++) sum=sum+i; cout<<"sum of "<<n<<" natural numbers ="<<sum; getch(); }
Find the mean of n natural numbers?
Mean = (sum of the n numbers)/n
How do you get the sum of consecutive cubed numbers?
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
What is the sum of the first 50 natural numbers?
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Program to calculate the sum of first ten natural numbers?
Algorithm to find the sum of first n natural numbers:1. Read n.2. Initialize N=1.3. Initialize sum S=0.4. Calculate S=S+N.5. Calculate N=N+1.6. If N>n, then goto step 7 else goto step 4.7. Write the sum S.8. Stop.
How do you calculate the sum of all numbers from 1 through 61?
The sum of the first "n" numbers is equal to n(n+1)/2.
What is the formula to find out the sum of first n even numbers?
n*(n+1)
