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The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
3
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
That would be -5.
0 + 2 + 3 = 5 2 + 3 + 5 = 10 3 + 5 + 10 = 18 5 + 10 + 18 = 33
1 3 5 8 20 18 10
1, 4, 7, 10, 13, ... (Arithmetic sequence, start with 1, add 3 for each successive term);10, 5, 2.5, 1.25, 0.625, ... (Geometric sequence, start with 10, halve for each successive term);2, 3, 5, 7, 11, 13, 17, ... (Prime numbers, no simple rule).
1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7
The nth term of the sequence is 2n + 1.
2 5 10 17 26 37 50 65 82 (3+5+7+9+11...)
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
3 11
3
4 5 6 7 8 9 10 11 12 13
The next term is 45 because the numbers are increasing by increments of 3 5 7 9 and then 11