Find a four digit number whose digits will be reversed when multiplied by nine?
The greatest number is 7.
Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number
A two digit number whose two digits added together equal 42 and multiplied together equal 82
The number is 21978. 21978 when multiplied by 4 which gives the result 87912 which is in reverse order.
Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
2 digit number
987654321 is the highest nine-digit number with no repeated digits.
The largest ten digit number with no repeated digits is '9876543210'.
Any prime numbers of about 66 or 67 digits will do.
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.
The largest number with no repeated digits is 9,876,543,210 although it is 10 digits long, the largest 3 digit number with no repeated digits is 987
146..4 is the second largest digit from a no
102 is the smallest three digit number with different digits.
The greatest 4-digit number with no repeated digits is... 9876
Any number that has 4 or 5 digits. A digit in a number is one number place. 1 has 1 digit, 11 has 2 digits, 111 has 3 digits, and so on.
There are a lot of possibilities. The second digit can be 2 through 6, the third digit can be 3 through 7 as long as it is larger than the second digit. What we have so far: 1 _ _ 89
Just compare the digits one by one: compare the first digit after the decimal point with the first digit of the other number, the second digit with the second digit, etc., until you find a digit that is different.
Let the first and third digits be equal. Choose any other number as the second digit. 202, 919, etc.