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If you mean: +3 +1 -1 -3 then it is -5

Q: What is the 5th term of the given sequence 31-1-3.....?

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That depends what the pattern of the sequence is.

0.16

"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."

Nth number in an arithmetic series equals 'a + nd', where 'a' is the first number, 'n' signifies the Nth number and d is the amount by which each term in the series is incremented. For the 5th term it would be a + 5d

If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46

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That depends what the pattern of the sequence is.

16

0.16

As you are taking 3 away each time, the 5th term will be -5.

"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."

Nth number in an arithmetic series equals 'a + nd', where 'a' is the first number, 'n' signifies the Nth number and d is the amount by which each term in the series is incremented. For the 5th term it would be a + 5d

56

Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)

If the sequence is 1,4,10,19,31,...... Then the sequence formula is, 1 + 3/2n(n - 1) Confirm 5th term....1 + (3/2 x 5 x 4) = 1 + 30 = 31 the 6th (next) term = 1 + (3/2 x 6 x 5) = 1 + 45 = 46

what is the bleeding sequence on rear brakes for a 2001 Honda prelude

first you need to write your equation. This is an exponential function so the equation would be- A(N)=a(b)^n-1 where a is the first term in the sequence (for you a=-14) b is the common ratio (for you b=1/2) and n= the number of term in your sequence (for you n=5, but it can be any number you want to find the nth sequence of.) Now take the equation a(n)=a(b)^n-1 and plug in your variables- Now your equation is a(5)=-14(1/2)^5-1 The first step to solving this is simplifying your exponent- so subtract 1 from five then your equation would read a(5)=-14(1/2)^4 Now solve the exponent then you would have a(5)=-14(1/16) then all you have to do is multiply a(5)=-7/8 So the fifth term in your sequence is -7/8 I hope this helped. :)

U5 = a + 5n = 4 U7 = a + 7n = 10 Therefore 2n = 6 and so n = 3 and then a = 4 - 5n = 4 - 15 = -11 So Un = -11 + 3n and therefore, U10 = a + 10n = -11 + 10*3 = -11 + 30 = 19