I think that each number is the previous one plus 8; 7+8=15 15+8=23 23+8=31 31+8=39 39+8=47
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8n + 7
t(n) = 3n2 + n + 1
2n^2-1
+9
a (sub n) = 35 - (n - 1) x d
Type your answer here... The next numbers in the sequence are 55, 70, 87, 106, 127, etc.
Assuming this is a linear or arithmetic sequence, the nth term is Un = 31 - 8n. But, there are infinitely many polynomials of order 5 or higher, and many other functions that will fit the above 5 numbers.
the nth term is = 31 + (n x -9) where n = 1,2,3,4,5 ......... so the 1st term is 31+ (1x -9) = 31 - 9 =22 so the 6th tern is 31 + (6 x -9) = -23 Hope this helps
t(n) = 3n2 + n + 1
31 - n
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
what will the eight number be. 1, 7, 13, 19, 25, 31 ...
The pattern is: +11, +15, +19, +23, +27 (4n+7) So, the next number would be: (4*6 + 7) = 24 + 7 = +31 Therefore, the answer is: 105 + 31 = 136
+9
a (sub n) = 35 - (n - 1) x d
(5/31) / (15/23) = (5/31)*(23/15) = (5*23)/(31*15) = (1*23)/(31/3) = 23/93
2n^2-1
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.