The question seems to be incorrect because, if the definition is 2n + 3 then the third tern should be 9 and the fourth one 11. In that case,
t(6) = 2*6 + 3 = 12+3 = 15
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
5, 8, 11, 14 and 17.
8, 9, 10, 11, 12, . . . etc.
94-1-6-11
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
4 5 6 7 8 9 10 11 12 13
5, 8, 11, 14 and 17.
In this case, 22 would have the value of 11.
The counting sequence is making increments of 11,that is, the n-th term will = 11 x nn = 12,t = 12 x 11= 132
8, 9, 10, 11, 12, . . . etc.
The nth term of the sequence is 2n + 1.
The nth term in this sequence is 4n + 3.
3 11
94-1-6-11
It seems each term(except the first one obviously) is generated by adding 11 to previous one. 4 15 = 4 + 11 26 = 15 + 11 37 = 26 + 11 The next term in the sequence will be then: 48 = 37 + 11