The question seems to be incorrect because, if the definition is 2n + 3 then the third tern should be 9 and the fourth one 11. In that case,
t(6) = 2*6 + 3 = 12+3 = 15
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
5, 8, 11, 14 and 17.
8, 9, 10, 11, 12, . . . etc.
The nth term in the sequence -5, -7, -9, -11, -13 can be represented by the formula a_n = -2n - 3, where n is the position of the term in the sequence. In this case, the common difference between each term is -2, indicating a linear sequence. By substituting the position n into the formula, you can find the value of the nth term in the sequence.
94-1-6-11
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The sequence n plus 3 can be represented as 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ... The 10th term of this sequence can be found by substituting n = 10 into the formula, which gives us 10 + 3 = 13. Therefore, the 10th term of the sequence is 13.
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
5, 8, 11, 14 and 17.
In this case, 22 would have the value of 11.
The counting sequence is making increments of 11,that is, the n-th term will = 11 x nn = 12,t = 12 x 11= 132
8, 9, 10, 11, 12, . . . etc.
The nth term of the sequence is 2n + 1.
The nth term in the sequence -5, -7, -9, -11, -13 can be represented by the formula a_n = -2n - 3, where n is the position of the term in the sequence. In this case, the common difference between each term is -2, indicating a linear sequence. By substituting the position n into the formula, you can find the value of the nth term in the sequence.
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
The given sequence is an arithmetic sequence with a common difference of 7 (18-11=7, 25-18=7, and so on). To find the nth term of an arithmetic sequence, you can use the formula: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the position of the term, and d is the common difference. In this case, the first term a_1 is 11 and the common difference d is 7. So, the nth term of this sequence is 11 + (n-1)7, which simplifies to 11 + 7n - 7, or 7n + 4.
The nth term in this sequence is 4n + 3.