The question seems to be incorrect because, if the definition is 2n + 3 then the third tern should be 9 and the fourth one 11. In that case,
t(6) = 2*6 + 3 = 12+3 = 15
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
5, 8, 11, 14 and 17.
8, 9, 10, 11, 12, . . . etc.
94-1-6-11
One of the infinitely many possible rules for the nth term of the sequence is t(n) = 4n - 1
an = an-1 + d term ar-1 = 11 difference d = -11 ar = ar-1 + d = 11 - 11 = 0 The term 0 follows the term 11.
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
The sequence n plus 3 can be represented as 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ... The 10th term of this sequence can be found by substituting n = 10 into the formula, which gives us 10 + 3 = 13. Therefore, the 10th term of the sequence is 13.
5, 8, 11, 14 and 17.
In this case, 22 would have the value of 11.
The counting sequence is making increments of 11,that is, the n-th term will = 11 x nn = 12,t = 12 x 11= 132
8, 9, 10, 11, 12, . . . etc.
The nth term of the sequence is 2n + 1.
I believe the answer is: 11 + 6(n-1) Since the sequence increases by 6 each term we can find the value of the nth term by multiplying n-1 times 6. Then we add 11 since it is the starting point of the sequence. The formula for an arithmetic sequence: a_{n}=a_{1}+(n-1)d
The nth term in this sequence is 4n + 3.
94-1-6-11
3 11