length = 7.2 units and width = 5.4 units
Solved by means of Pythagoras' theorem.
a=3 b=2 c=diagonal a squared add b squared equals c squared 9 add 4 = 13 square root 13 and ther's your answer
The area of a rectangle is the length times the width. In this case, 15' x 9' = 135 ft2.
The area of a rectangle is always length multiplied by width. Therefore, the area of the mentioned rectangle is 36cm2.
The dimensions of the rectangle are 21 units by 9 units
Length = 9 Width = 9 Your rectangle is a square.
To find the diagonal length of a rectangle use Pythagoras' theorem for a right angle triangle.
Using Pythagoras' theorem it is about 10.81665383 inches.
width=9 length=18
The area of a rectangle with a width of 9 and length of 23 is 207 square units.
9
a=3 b=2 c=diagonal a squared add b squared equals c squared 9 add 4 = 13 square root 13 and ther's your answer
15 cm for the diagonal.
Area of a rectangle is length times width, therefore if the length is two feet longer than the width then the length is 9 and the width is 7, when they are multiplied you get 63
length is 3 and width is 9
The area of a rectangle is the length times the width. In this case, 15' x 9' = 135 ft2.
The area of rectangle is : 27.0
The area of a rectangle is always length multiplied by width. Therefore, the area of the mentioned rectangle is 36cm2.