Equation: y--3 = -3(x-0) => y = -3x-3
The Slope of a line containing the points (2,2) and (4,2) is Y=0
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
(3--4)/2--6) = 7/8 which is the slope of the line.
If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.
Zero
y = 2x + 1.
The Slope of a line containing the points (2,2) and (4,2) is Y=0
Another coordinate is needed to determine the slope of the line.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
If you mean (-2, 5) then another coordinate is needed in order to determine the slope of the line
(3--4)/2--6) = 7/8 which is the slope of the line.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
Zero
The equation of a line in slope-intercept form is given by y = mx + b, where "m" represents the slope of the line and "b" represents the y-intercept.