y = 1
x = 0 and y = 4
you cant
yes it is..your welcome
yes
5y + 7 = 25y = -5y = -1
x = (-5y + 4) / 7
(2, 3) is a solution only if it satisfies the equation. x + 5y = 4 (2) + 5(3) =? 4 2 + 15 =? 4 17 = 4 False Therefore, (2, 3) is not a solution to the given equation.
8 - 5y = 12 -5y = 4 y = -4/5
If: 4x = 5y Then: x = 5y/4
5y + x = 0 subtract 5y from each side, then x = -5y
No solution
5y-4 = 7 5y = 7+4 = 11 y = 11 / 5 = 2.2