The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.
It will have 35 sides
no polygon can have its angle sum be 1660 degrees. the closest shape would be a 11 sides shape
A polygon with n sides inscribed in a circle has an angle sum of 180xn-360 So the problem is find n so that 180n-360=9000 => n=48 The regular polygon with an angle sum of 9000 has 48 sides
There is no regular polygon with an interior angle of 20o. If the interior angle is 120o then there are six sides and the sum of the angles is 720o.
No. The sum of the exterior angles of a polygon sum to 360o For a regular polygon, they are all the same size ⇒ dividing 360o by the exterior angle gives the number of sides. Interior angle = 154o ⇒ exterior angle = 180o - 154o = 26o ⇒ number of sides = 360o ÷ 26o = 1311/13 sides But a polygon must have a whole number of sides ⇒ 154o cannot be the interior angle of a regular polygon.
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.
The sum of the exterior angles of a regular polygon equal 360° . If one such angle measures 36° then the polygon has 360/36 = 10 sides.
The sum of the exterior angles of a regular polygon equal 360° .If one such angle measures 40° then the polygon has 360/40 = 9 sides.
For a regular polygon with sides n, the sum of the interior angles = (n-2)180Therefore, a regular polygon has interior angle sum equal to 540o.(5-2)180=(3)180=540
360/14 = 25.7143o.
A regular polygon with 17 sides has exterior angles that add up to 360. That is the sum of the exterior angles no matter how many sides a regular polygon has. The sum of the interior angles is (n-2) 180 degrees where n is the number of sides. In this case that is 15x180 which is 2,700
360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360