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How do you find the interior angle of a polygon?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. Once you have the sum, divide by the number of sides to find an individual angle.
If the sum of the interior angle measures of a polygon is 1260 how many sides does the polygon have?
We solve the equation for n... since the sum of the interior angles is 180(n-2) where n is the number of sides of the polygon. So we have: 180(n-2)=1260 n-2=7 n=9 So 9 sides
What is the sum of the interior angle measures of a polygon?
(number of sides-2)*180 = total sum of interior angles
What is the sum of the interior angles of a regular polygon with ten sides?
A regular polygon with 10 sides is called a decagon. The formula of angle sums of a polygon is: Angle Sums = (n - 2)180° where n = number of sides. So, Angle Sums = (10 - 2)180° = 8 x 180° = 1,440°
How many sides does a polygon with an interior angle measure of 1080 have?
If the polygon has n sides, the sum of its interior angles is 180*(n-2) = 1080 So n-2 = 1080/180 = 6 And therefore n = 8
