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-6x = 6y + 6

-6x = 3y - 12

Subtracting the second from the first gives:

-6x - -6x = 6y - 3y + 6 - -12

→ 0 = 3y + 18

→ 3y = -18

→ y = -6

Substituting in the first:

-6x = 6y + 6

→ -6x = 6(-6) + 6

→ -6x = -36 + 6

→ -6x = -30

→ x = 5

Thus x = 5, y = -3 solve the simultaneous equations.

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Q: What is the answer of -6x equals 6y plus 6 and -6x equals 3y -12?
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