(r+t)/rt
Given T = R + RS Lateral inversion makes it to be R + RS = T Taking R as common factor, we get R(1+S) = T Now dividing by (1+S) both sides, R = T / (1+S) Hence the solution R = T/(1+S)
5t + 1
r=0,Tr-r = 0 = r(T-1), since T != 1, then T-1 is non zero so r must be zero.
SMILE
If f(t) = t5 + t4 + t3 + t2 + t + 1 then remainder when divided by t+1 is f(-1) The remainder is, therefore, (-1)5 + (-1)4 + (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 - 1 + 1 = 0
2d+2h+2t+g+f+2r+w+x
2/3 + 1/3 = 1
2r + 7r - 6t - r + 7t = 8r + t
v
That statement is always true, no matter what number 'T' is. There's no reason for your brain to get teased over it.
t=1
1-800 get-a-life