10+r = 2r Subtract r from both sides:- r = 10
r = 5k + 5ur - 5u = 5kk = r/5 - u
Let y=ce^(rx). R^2+r+1=0. Quadratic equation to find R.
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A Diophantine Equation. In order to solve it, you should use Euclide's algorithm.
r + 11 + 8r = 29
Congratulations! You already have. h = S+r
10+r = 2r Subtract r from both sides:- r = 10
r + 11 = 19 r + 11 - 11 = 19 - 11 r = 8
r = 5k + 5ur - 5u = 5kk = r/5 - u
You subtract 11 from both sides and r equals negative 7. See... r+11=3 -11 -11 r=7
(2-r)e-rr
Let y=ce^(rx). R^2+r+1=0. Quadratic equation to find R.
You add 12... r + (-12) = 19 r + (-12) + 12 = 19 + 12 r = 31
r = 3 s = 5 t = 6 rs = 3x5 = 15 rt = 3x6 = 18 st = 5x6 = 30
If r-squared = theta then r = ±sqrt(theta)
r=-29