If you mean t^2 +11t +10 then it is (t+10)(t+1) when factorized
If f(t) = t5 + t4 + t3 + t2 + t + 1 then remainder when divided by t+1 is f(-1) The remainder is, therefore, (-1)5 + (-1)4 + (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 - 1 + 1 = 0
(t + 7)(t - 1)
T(t + 4)
x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4
If you mean t^2 +11t +10 then it is (t+10)(t+1) when factorized
If f(t) = t5 + t4 + t3 + t2 + t + 1 then remainder when divided by t+1 is f(-1) The remainder is, therefore, (-1)5 + (-1)4 + (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 - 1 + 1 = 0
(t + 7)(t - 1)
T(t + 4)
If t2 + t + 3 = 0 then[moving the 3 to the other side of the equation]t2 + t = -3[adding a value to both sides of the equation allowing us to easily factor the expression - i.e. completing the square]t2 + t + 1/4 = -3 + 1/4[factoring the expression: t2 + t + 1/4 factors to (t + 1/2) (t + 1/2) i.e. (t + 1/2)2 ](t + 1/2)2 = -3 + 1/4(t + 1/2)2 = -2.75[now square root each side]t + 1/2 = -2.751/2t = -2.751/2 - 1/2[the square root of -2.75 is equal to the square root of 2.75 * the square root of -1. The square root of -1 is an imaginary number represented by the letter "i"]t = (2.751/2 * -11/2) - 1/2t = (2.751/2 * i) - 1/2[the square root of 2.75 has two answers (+ and -) which will provide the two roots to the quadratic]t = + or - 1.658i - 1/2 (to 3 decimal places only)To solve this equation we have used the technique of "completing the square" and have made use of the imaginary number "i".This equation does not have real roots as it involves the square root of a negative number and so this is the only way in which we can answer the question.
t4-81 is a difference of 2 squares and can be written as (t2-9)(t2+9) t2+9 can't be further factorised but t2-9 is a difference of 2 squares again and can be factorised to (t+3)(t-3) so the factors of t4-81 are :(t2+9)(t+3)(t-3) Hope this helps :-) I believe the answer you are looking for is (t - 3)(t + 3)(t 2 + 9)
(t - 7)(t - 11)
x2 is the same as x times x. In this case x = t+2 so we can say (t+2)2 is (t+2)(t+2) or t2+4t+4
,/` 2(1 - x) dx,/` 2 - 2x dx2x - x2 ...evaluated from 0 to t gives us...2t - t2 - [2(0) - (0)2]2t - t2
t2 - 59t + 54 - 82t2 + 60t = - 81t2 + t + 54
t2+ t - 42 it can't be simplified anymore
^E+W=Q.....................1 Q2-Q1/Q2=T2-T1/T2.....................2 W=Q2-Q1 Given W/Q =T2-T1/T2 T2-T1=^T and Q=^W ^w/Q=^T/T Q=T{^W/^T} PUTTING THE VALUE EQI {1} ^E+W=T^W/^T [GIBBS HELMHOLT EQUATION]