-3/2
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
x2 + 6x + 1 = 0 x2 + 6x + 9 = 8 (x + 3)2 = 8 x + 3 = ± 2√2 x + 3 = -3 ± 2√2 x ∈ {-3 - 2√2, -3 + 2√2}
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
If y=2 then that means x^2=9 and x= 3 or -3
x2 + 6x - 2 = 0 x2 + 6x + 9 = 13 (x + 3)2 = 13 x + 3 = ± √13 x = -3 ± √13
-4
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
2x^2 + 8x + 3 = 0
x=5/2*sqr(3)
(x - 3)(x - 2)