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x2 + 6x + 1 = 0

x2 + 6x + 9 = 8

(x + 3)2 = 8

x + 3 = ± 2√2

x + 3 = -3 ± 2√2

x ∈ {-3 - 2√2, -3 + 2√2}

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Q: X2 plus 6x plus 1 equals 0?
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