5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1
2L+2W=132 L=W+8 substitute for L... 2(W+8)+2W=132 2W+16+2W=132 4W+16=132 2W+8=66 2W=58 W=29 L=W+8=29+8=37 So the width is 29 metres and the length is 37 metres
Let w be the width, then 2(7 + w) = 42 or 14 + 2w = 42 or 2w = 42 - 14 or 2w = 28 w = 14
6 + w - 2w - 11 + 6w = -5 + 5w
P = perimeter, L = length, W = width P = 2L + 2W = 2(8) + 2W = 2W + 16 = 46 2W = 30 W = 15 So as long as x is 15 inches or more, it will have a perimeter at least 46.
w = 3 16 = 4w + 2w - 2 Move the 2 to other side 16 + 2 = 4w + 2w 18 = 6w 18 / 6 = 3 = w
2w + 16 = - 6w - 8 2w + 16 + 6w = - 8 8w + 16 = - 8 8w = - 8 - 16 8w = - 24 w = - 3
-36 + 2w = -8w + w -36 + 2w = -7w -36 = -7w - 2w -36 = -9w w = -36/-9 = 4
W/3 + 2W/3 is one possible answer.
w=4
Perimeter, P = 32 mArea, A = 60 m^2.A = LW60= LWL = 60/WP = 2L + 2W32= 2L + 2W substitute 60/W for L;32= 2(60/W) + 2W divide by 2 to both sides;16 = 60/W + W multiply by W to both sides;16W = 60 + W^20 = 60 + W^2 - 16W or,W^2 - 16W + 60 = 0W = [16 +,- square root of [16^2 - (4)(1)(60)]/2W = [16 +,- square root of (256 -240)]/2W = (16 +,- square root of 16)/2W = (16 + 4)/2 or W = (16 - 4)/2W = 20/2 or W = 12/2W = 10 m or W = 6 mL = 60/W = 60/10 or L = 60/6L = 6 m or L = 10 m
22
5w+2 = 2w+5 5w-2w = 5-2 3w = 3 w = 1
2L+2W=132 L=W+8 substitute for L... 2(W+8)+2W=132 2W+16+2W=132 4W+16=132 2W+8=66 2W=58 W=29 L=W+8=29+8=37 So the width is 29 metres and the length is 37 metres
w=10
Oh honey, solving for w in 2l + 2w = P is as easy as stealing candy from a baby. Just subtract 2l from both sides and then divide by 2. Voila, w = (P - 2l) / 2. Now go show off your math skills like the boss you are.
3w - 2 = 2w + 3 Add 2 to both sides: 3w = 2w + 5 Subtract 2w from both sides: w = 5