it equals x1 it equals x1
2x2+7/x1
The answer is: X1 = 2 X2 = -7
shut up and do your hw
sqr.rtx/x= sqrt.x*sqr.rtx/sqr.rtx=x/x*sqrt.x=1/sqrt.x. x1/2 = x1/2 * x1/2 = x = 1 (x1/2) /x= 1/x1/2
x² = x+110 x²-x-110 = 0 x1= -(-1/2) - Square root of ((1/2)²+110) x1 = 0.5 - 10.5 x1 = - 10 x2 = -(-1/2) + Square root of ((1/2)²+110) x2 = 0.5 + 10.5 x2 = 11
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
if sqrt(x) + 8 = 0, then: x1/2+8 = 0 x1/2 = -8 (x1/2)2 = (-8)2 x = 64 √x + 8 = 0 is a contradiction equation, because the equivalent equation √x = -8 is not a true statement, because √x = |x| = positive. So that, - √x + 8 = 0 is true for x = 64.
Construct the Lagrange interpolating polynomial P1(x) for f(x) = cos(x)+sin(x) when x0 = 0; x1 = 0:3. Find the absolute error on the interval [x0; x1].
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
4
x*x1/2= x3/2 Derivative = 3/2 * x1/2