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If you mean y2+8y+7=0 then it is a quadratic.
y2+8y+7+9-9=0
y2+8y+16-9=0
(y+4)2=9
y+4=3 , y+4=-3
y=-1 , y=-7
So y can equal -1 or -7.
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What is -8y - 7 equals -8 plus 8y?
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
Is 8y plus 7 a binomial?
yes
What is the solution to x2 plus 2y-6x plus 8y-1 equals x2-y2 plus 4x-6y-1?
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
What is the center and radius of the graph of the circle of x squared plus y squared plus 6x minus 8y minus 24 0?
x2 + y2 + 6x + 8y - 24 = 0 add 32, 42, and 24 to both sides to complete the squares (x2 + 6x + 32) + (y2 + 8y + 42) = 9 + 16 + 24 (x + 3)2 + (y + 4)2 = 49 [x - (-3)]2 + [y - (-4)]2 = 72 Center: (-3, -4) Radius: 7
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
What is Y2 plus 8y plus 16 equals 0?
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
How do you factor y2 plus 8y plus 16?
y2 + 8y + 16 = y2 + 4y + 4y + 16 = y(y + 4) + 4(y + 4) = (y + 4)(y + 4) or (y + 4)2
What is 2x plus 8y plus 7 equals 0?
2x = -7 - 8y
Factor y2-8y plus 15?
It goes to (x-5)(x-3)
What is 7 plus 8y-3y plus 2?
7 + 8y - 3y + 2 =7 + 2 + 8y - 3y = 9 + 8y - 3y = 9 + 5y
What is -8y - 7 equals -8 plus 8y?
If: -8y-7 = -8+8y Then: -7+8 = 8y+8y And: 16y = 1 So: y = 1/16
Is 8y plus 7 a binomial?
yes
What is the solution to x2 plus 2y-6x plus 8y-1 equals x2-y2 plus 4x-6y-1?
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
Find the center and radius of the circle given by the equation x2 plus y2-10x plus 8y plus 5 equals 0?
The standard equation of a circle with center C(h,k) and radius r is as follows:(x - h)2 + (y - k)2 = r2(x2 -2hx +h2) + (y2 - 2ky + k2)We have...x2 + y2 - 10x + 8y + 5 =0x2 - 10x + y2 + 8y + 5 =0add h2 and k2 to both sides(x2 - 10x + h2) + (y2 + 8y + k2) = -5 + h2 + k2Using the above framework we can see that 10 = 2h, h = 5Using the above framework we can see that 8 = 2k, k = 4So the formula is(x2 - 10x + 25) + (y2 + 8y + 16) = -5 + 25 + 16(x - 5)2 + (y - 4)2 = 36the center of the circle is C(5,4) and radius 6
What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
What is the center and radius of the graph of the circle of x squared plus y squared plus 6x minus 8y minus 24 0?
x2 + y2 + 6x + 8y - 24 = 0 add 32, 42, and 24 to both sides to complete the squares (x2 + 6x + 32) + (y2 + 8y + 42) = 9 + 16 + 24 (x + 3)2 + (y + 4)2 = 49 [x - (-3)]2 + [y - (-4)]2 = 72 Center: (-3, -4) Radius: 7
