Please be more specific with your question. If you mean 2cm, then the area will be 12cm squared. If you mean 2m then the area will be 12m squared.
The perimeter of a regular hexagon is (6 x the length of one side).
9 units
It is regular if all the sides are the same length and each interior angle is 120 degrees.
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
Assuming that the hexagon is regular (all sides are the same), it can be comprised of 6 equilateral triangles of side length 6 (in this case). Area of a equilateral triangle is: (side length^2*√3)/4 Each triangle is of area: 62.353829072479572 inches square. 62.353829072479572*6 = 374.12297443487743 inches square approx.
The perimeter of a regular hexagon is (6 x the length of one side).
To find the area of a regular hexagon with side length of 40cm, consider that since it is regular, then it consists of 6 equilateral triangles of side 40cm. Half of each of those triangles is a right triangle. By the pythagorean theorem, we know that if the hypotenuse is 40cm, and one side is 20cm, then the other side is the square root of (40cm squared - 20cm squared) or about 34.64cm. That makes the area of each of those 12 right triangle to be about 692.8cm, so the total area of the hexagon is about 8313.8cm.
The volume of a standard hexagon can be given by the product of 6 times the length of one side of the hexagon and the height. Note that for a hexagon to have volume, it must have another dimension that is height.
A regular hexagon can be considered as being built up of six equilateral triangles. Each equilateral triangle has an area of (b/2) * sqrt (3b/2) where b is the side of the equilateral triangles that make up the hexagon and also the radius of the hexagon's circumscribed circle, and sqrt means the square root ofSo the area of the regular hexagon with side length b is 3 * b * sqrt (3b/2)
How many sides has a hexagon? What is the length of each side? Over to you....
Half the length from one vertice to its opposite.
9 units
Divide by six since a hexagon has six sides: 54 / 6 = 9mm
Side length x 6 = perimeter
It is regular if all the sides are the same length and each interior angle is 120 degrees.
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
It depends on a few factors: if the angle is interior, if the angle is exterior, and if the hexagon is a regular hexagon or not. Each interior angle of a regular hexagon is 120o. Each exterior angle of a regular hexagon is 60o.