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What is the area of a hexagon with side length of 10?
To calculate the area of a regular hexagon, you can use the formula: Area = (3√3 × side length²)/2. Substituting the value of the side length given, the area of a hexagon with a side length of 10 is (3√3 × 10²)/2 = 150√3. Therefore, the area is approximately 259.81 square units.
What is the area of a reagular hexagon with the side length of 10?
The area of a reagular hexagon with the side length of 10 is 51.96 square units
What is the area of a regular hexagon with side lengths of 10 units?
The area of a regular hexagon with side lengths of 10 units is about 259.8 units2
What is the area of a hexagon with the side length of 10?
The area of a regular hexagon is given asA = (3*root 3)/2*t = approx 2.59807621 * tWhere A = Area and t = edge length.so if t = 10then A = 2.59807621 * 10 = 25.9807621
A regular hexagon has sides 10 cm long what is the area?
259.8
What is the area of a hexagon with side length of 10?
To calculate the area of a regular hexagon, you can use the formula: Area = (3√3 × side length²)/2. Substituting the value of the side length given, the area of a hexagon with a side length of 10 is (3√3 × 10²)/2 = 150√3. Therefore, the area is approximately 259.81 square units.
What is the area of a reagular hexagon with the side length of 10?
The area of a reagular hexagon with the side length of 10 is 51.96 square units
What is the area of a regular hexagon with side lengths of 10 units?
The area of a regular hexagon with side lengths of 10 units is about 259.8 units2
What is the area of a hexagon with the side length of 10?
The area of a regular hexagon is given asA = (3*root 3)/2*t = approx 2.59807621 * tWhere A = Area and t = edge length.so if t = 10then A = 2.59807621 * 10 = 25.9807621
A regular hexagon has sides 10 cm long what is the area?
259.8
Find the area of a regular hexagon with a base of 10 and an apothem of 12?
14
What is the area of a hexagon with a side of 10 inches and an apothem of 8 inches?
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
What is the area of a regular hexagon with a side length of 10 meters and a distance from the center to a vertex of 10 meters?
area = 3 x (radius to point) squared x sin 60 degrees =3(10)(10)(.866) = 259.8 sq m
Can you relate the area of triangle and the area of hexagon?
Area of hexagon= Area of original triangle/10
What is the Area of a regular hexagon with a base of 10 and an apothem of 20?
12 x 5 x 20 ie 1200squnits. I'm not convinced you can have such a hexagon, if the side is 10 then shouldn't the apothem have to be 5 root 3?
Can you show that you can work out the area of a regular hexagon with a perimeter of LX inches rounding your answer to a suitable degree of accuracy?
Perimeter in inches = LX = 60. A regular hexagon with a perimeter of 60 inches has 6 equal sides of 10 inches. A regular hexagon has 6 equal interior equilateral triangles So in order to find the area of the hexagon we must first find the area of one of its interior triangles and then multiply the result by 6. Area of a triangle = base times perpendicular height divided by 2. An equilateral triangle can be considered as being two right angled triangles joined together. So by halving the length of its base we can find its perpendicular height by using Pythagoras' Theorem: hypotenuse2-base2 = perpendicular height2. 102-52 = 75 square inches. Square root of 75 = 8.660254038 inches. Area of the equilateral triangle = 10*8.660254038/2 = 43.30127019 square inches. Area of the regular hexagon = 43.30127019*6 = 259.8076211 square inches. Therefore the area of a regular hexagon with a perimeter of 60 inches is 260 square inches which is correct to 3 significant figures.
What is the approximate surface area of a regular tetrahedron with edge length 10 cm?
173
