The area is 56 cm2
If those are the diagonals of the rhombus then its area: 0.5*14*8 = 112 square cm
The lengths of the diagonals work out as 12 cm and 16 cm
56 cm squared
Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.
Let the diagonals be x+5 and x:- If: 0.5*(x+5)*x = 150 sq cm Then: x2+5x-300 = 0 Solving the above by means of the quadratic equation formula: x = +15 Therefore: diagonals are 15 cm and 20 cm The rhombus has 4 interior right angle triangles each having an hypotenuse Dimensions of their sides: 7.5 and 10 cm Using Pythagoras' theorem: 7.52+102 = 156.25 Its square root: 12.5 cm Thus: 4*12.5 = 50 cm which is the perimeter of the rhombus Note: area of any quadrilateral whose diagonals are perpendicular is 0.5*product of their diagonals
14*8 = 112 sq cm
If those are the diagonals of the rhombus then its area: 0.5*14*8 = 112 square cm
54
Answer63cm2. False
The lengths of the diagonals work out as 12 cm and 16 cm
the diagonals of a rhombus measure 16 cm and 30 cm.find its perimeter.
The maximum area for a rhombus occurs when the rhombus is a square, as all sides are equal in length. Since the sides of the rhombus are 25 cm each, the area of the square rhombus would be calculated by squaring the length of one of the sides, which is 25 cm, resulting in an area of 625 square cm. Thus, the maximum area for a rhombus with sides of 25 cm is 625 square cm.
1/2 x 8 x 7 = 28cm2
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
always
Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm
112