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What is the area of this rhombus if AC equals 14 cm DB equals 8 cm?
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∙ 13y ago
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Wiki User
∙ 13y ago
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What is the area of a rhombus if ac is 14cm and db is 8cm?
AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112
In rhombus abcd bd equals 6 and ac equals 8 what is the length of each side?
5 units
AC equals 3 AD equals 8 and CE equals 18?
435
If AE equals 8x - 3 and EC equals 6x plus 7 then AC equals?
5
If AE equals 8x-3 and 6x plus 7 then AC equals?
74
AC equals 14 cm DB equals 8 cm What is the area of this rhombus?
56 cm squared
What is the area of this rhombus if ac equals 14cm and db equals 8cm?
Well, the area of a rhombus is 1/2*d(1)*d(2). 1/2 * 8 * 14 is 56, so the area of this rhombus is 56 square cm.
What is the area of a rhombus if ac equals 14 bd equals 17 and ab equals 11?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119
What is the area of rhombus ABCD if AC equals 11 and BD equals 7?
38.5
What is the area of rhombus ABCD if AC equals 9 and BD equals 13?
31.5 Square Units
What is the area of rhombus ABCD if AC equals 7 and BD equals 9?
31.5 square units
What is the area of a ABCD rhombus when angle AC equals 14 and angle BD equals 17?
An angle is not normally defined by two characters. Also, a rhombus cannot have two angles whose measures are 14 and 17: any two angles MUST be complementary or equal.
What is the area of rhombus ABCD if AC equals 8 and BD equals 9?
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
What is the area of this rhombus ac14cm db8cm?
If ac and bd are diagonals then area of rhombus = 1/2 x ac x bd Area = 1/2 x 14 x 8 cm2 = 56 cm2
What is the area of a rhombus if ac is 14cm and db is 8cm?
AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
What is thr area of the rhombus shown below AC 17 BD15 AB11.2?
Area of a rhombus: base times perpendicular height Or area of a rhombus: 0.5 times product of its diagonals
