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What is the area of this rhombus if ac equals 14cm and db equals 8cm?
Well, the area of a rhombus is 1/2*d(1)*d(2). 1/2 * 8 * 14 is 56, so the area of this rhombus is 56 square cm.
What is the area of rhombus ABCD if AC equals 11 and BD equals 7?
38.5
What is the area of rhombus ABCD if AC equals 7 and BD equals 9?
31.5 square units
What is the area of rhombus ABCD if AC equals 9 and BD equals 13?
31.5 Square Units
What is the area of this rhombus ac14cm db8cm?
If ac and bd are diagonals then area of rhombus = 1/2 x ac x bd Area = 1/2 x 14 x 8 cm2 = 56 cm2
What is the area of this rhombus if AC equals 14 cm DB equals 8 cm?
112
What is the area of this rhombus if ac equals 14cm and db equals 8cm?
Well, the area of a rhombus is 1/2*d(1)*d(2). 1/2 * 8 * 14 is 56, so the area of this rhombus is 56 square cm.
What is the area of a rhombus if ac equals 14 bd equals 17 and ab equals 11?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119
What is the area of rhombus ABCD if AC equals 11 and BD equals 7?
38.5
What is the area of rhombus ABCD if AC equals 7 and BD equals 9?
31.5 square units
What is the area of rhombus ABCD if AC equals 9 and BD equals 13?
31.5 Square Units
What is the area of a ABCD rhombus when angle AC equals 14 and angle BD equals 17?
An angle is not normally defined by two characters. Also, a rhombus cannot have two angles whose measures are 14 and 17: any two angles MUST be complementary or equal.
What is the area of rhombus ABCD if AC equals 8 and BD equals 9?
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
What is the area of this rhombus ac14cm db8cm?
If ac and bd are diagonals then area of rhombus = 1/2 x ac x bd Area = 1/2 x 14 x 8 cm2 = 56 cm2
What is the area of a rhombus if ac is 14cm and db is 8cm?
AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
What is thr area of the rhombus shown below AC 17 BD15 AB11.2?
Area of a rhombus: base times perpendicular height Or area of a rhombus: 0.5 times product of its diagonals
