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What is the area of a rhombus that has a perimeter of 80 cm when one of its diagonals is 24 cm?
Wiki User
∙ 6y ago
Its other diagonal works out as 32 cm using Pythagoras' theorem
It will have 4 right angle triangles of 20 cm by 16 cm by 12 cm
Its area is: 0.5*32*24 = 384 square cm
Its area is also: 0.5*16*12*4 = 384 square cm
Wiki User
∙ 6y ago
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1 property about the diagonals of a rhombus have?
The diagonals of a rhombus bisect one another.
Area of a rhombus with diagonals of 8 ft and 10 ft?
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
The area of a rhombus equals one-half times the sum of the lengths of its diagonals?
false
What is the perimeter of a rhombus when one of its diagonals is 7.5cm and has an area of 37.5 square cm?
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
The diagonals of a rhombus are perpendicular bisectors of one another?
True, the diagonals of a rhombus are perpendicular bisectors of one another.
What is the area of a rhombus if one of the diagonals is ten cm and the perimeter is fourteen cm?
Answer63cm2. False
1 property about the diagonals of a rhombus have?
The diagonals of a rhombus bisect one another.
Area of a rhombus with diagonals of 8 ft and 10 ft?
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
What is the perimeter of a rhombus when one of its diagonals is 7.5cm and has an area of 37.5 square cm?
Let the other diagonal be x:- If area is: 0.5*x*7.5 = 37.5 Then x is: 37.5/(0.5*7.5) = 10 The rhombus will then have 4 right angles with sides of 5 and 3.75 Using Pythagoras: hypotenuse of each triangle is 6.25 cm Therefore perimeter of the rhombus is: 4*6.25 = 25 cm
The area of a rhombus equals one-half times the product of the lengths of its diagonals?
True
The area of a rhombus equals one-half times the sum of the lengths of its diagonals?
false
The diagonals of a rhombus are perpendicular bisectors of one another?
True, the diagonals of a rhombus are perpendicular bisectors of one another.
What is the area and perimeter of a rhombus?
Area equals base times height. The perimeter is 4 times the length of one side.
What is the area of rhombus one side of which measures 20cm and one diagonal 24 cm?
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
What is the area of a rhombus when one of its diagonals is 11.8 cm in length and has a perimeter of 29 cm showing work and answer?
Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.
What is the area of a rhombus with diagonals of 12 and 5?
The diagonals bisect each other. Since that is true then the area of the rhombus is the sum of the two triangles. Half of one diagonal times the other diagonal.2(6x5)/2 or 6x5=30
What are the diagonals in a rhombus?
The diagonals of a rhombus are lines drawn from one corner, or vertex, to the opposite one. They have two important properties. 1. Diagonals bisects a pair of opposite angles. 2. Diagonals are !!perpendicular!!
