True
If you are wanting the area of a rhombus that have diagonals which lengths are 3 and 12, then the area is 18 square units.
You need more information: the length of a side. Then, since the diagonals bisect one another at right angles, you can use Pythagoras's theorem to calculate their lengths.
AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112
Oh, dude, it's like the diagonals in a rhombus are totally those lines that connect the opposite corners. They're like the fancy crossroads of the rhombus world, making all those right angles and stuff. So yeah, if you ever need to find them, just look for those lines that cut the rhombus in half diagonally.
7
false
Half the product of the lengths of its diagonals. A=1/2(d1*d2)
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
The lengths of the diagonals work out as 12 cm and 16 cm
noNo, the diagonals of a rhombus are perpendicular to each other.Unless the rhombus is regular (and called a square) the diagonals are of different lengths.
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
the answer is 20
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119
The sides of a rhombus must all be the same length, but the angles do not need to be the same. The result is a diamond shape where the diagonals can be two different lengths.
false
It is a rhombus
The diagonals of a rhombus bisect one another at right angles. So you can use Pythagoras on half the lengths of the diagonals. If the two diagonals ore of lengths a and b, then side2 = (a/2)2 + (b/2)2 or, equivalently, side = 1/2*sqrt(a2 + b2)