8
165.8 sq cm
Assuming the height is 13 inches (not 13 feet or something else), Area = 0.5*(12+14)*13 = 169 sq inches.
6
The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.
135.15 sq. cm
Isosceles trapezoid ABCD has an area of 276 If AD = 13 inches and DE = 12 inches, find AB.
28.00
165.8 sq cm
Assuming the height is 13 inches (not 13 feet or something else), Area = 0.5*(12+14)*13 = 169 sq inches.
6
If the area is 221 square units and the width is 17 units then the length will be 13 units because 17*13 = 221 square units.
The area of a trapezoid is 1/2 times the sum of the bases * the height. In this case, we have the area of 65 = 1/2 * (13+13) * height. Solving for height, we have 65 * 2 / 26, so h = 5. If the two bases of a quadrilateral are of the same length, it is not a parallelogram, but a rectangle.
135.15 sq. cm
52 square units
31.5 Square Units
1 divided by 13 equals 13
First, you would add 13+13, which equals 26. Then you would subtract 26-13 which equals 13. So the problem would be 26-13=13.