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Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
Base = Area/Height = 7886.2/95.7 = 82.405 cm (to 3 dp)
94cm,
What is the density of a rectangular object with the height of 5 cm the length of 10 cm, the width of 2 cm and the mass of 50 g
5.5 cm
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
Rhombus Area = side x height = 6 cm x 4 cm = 24 cm2In the right triangle formed by the side and the height of the rhombus, we have:sin (angle opposite to the height) = height/side = 4 cm/6cm = 2/3, so thatthe angle measure = sin-1 (2/3) ≈ 41.8⁰.In the triangle formed by two adjacent sides and the required diagonal, which is opposite to the angle of 41.8⁰ of the rhombus, we have: (use the Law of Cosines)diagonal length = √[62 + 62 -2(6)(6)cos 41.8⁰] ≈ 4.3Thus, the length of the other diagonal of the rhombus is about 4.3 cm long.
always
24 cm sq
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.
Base = Area/Height = 7886.2/95.7 = 82.405 cm (to 3 dp)
volume = length x width x height height = volume / (length x width) height = 378 cm3 / (6cm x 7cm) = 9 cm
94cm,
A rectangular prism with length 7 cm, width 4 cm and height 6 cm has a volume of 168cm3
A rectangular prism that has a length of 7 cm, width of 8 cm and height of 14 cm has a volume of 784cm3
A rectangular prism with a length of 4 cm, a width of 2 cm and a height of 5 cm has a volume of 40cm3
Quokkas are not generally measured in height, but in head to body length, which gives a rough range of the quokka's height. They have a head to body length of between 41 cm and 54 cm, with a tail length of 25 - 31 cm.