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Equation: 2x^2 +2y^2 +2x -6y -9 = 0

Divide all terms by 2: x^2 +y^2 +x -3y -4.5 =0

Completing the squares: (x+1/2)^2 +(y-3/2)^2 -1/4 -9/4 -4.5 = 0

So: (x+1/2)^2 +(y -3/2)^2 = 7

Centre of circle: (-1/2, 3/2)

Radius of the circle is the square root of 7

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Q: What is the center and radius of a circle whose equation is 2x squared plus 2y squared plus 2x -6y -9 equals 0?
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