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8 - 8i

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Q: What is the complex conjugate of 8 plus 8i?
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Related questions

What is the complex conjugate of 8 plus 9i?

It would be 8 minus 9i or 8-9i


What is the complex conjugate of 8?

8


What is the complex conjugate complex number-8-6i?

-6i-8


What is the polar form of -8 plus 8i?

It's 8 sqrt(2) at an angle of 135° .


What imaginary number is equivalent to the square root of negative 64?

8i and -8i both satisfy this: (8i)² = (8²)(i²) = (64)(-1) = -64, and (-8i)² = (-8²)(i²) = (64)(-1) = -64


What is the answer for -8i-7i?

Numbers of the form a + ib (where i = -11/2; a and b are real numbers) are called complex numbers.For any two complex numbers (a+ib) and (c+id):Addition:(a+ib) + (c+id) = (a+c) + i(b+d)So, -8i-7i = (-8-7)i = -15i


What is the complex conjugate complex number 8 6i?

Since you didn't show an operator, we'll use: 1. 8-6i 2. 8+6i 3. 8 times 6i = 48i The complex conjugates are: 1. 8+6i 2. 8-6i 3. -48i


What is the radix of x2-10x plus 31 equals 0 is x equals 5 and x equals 8?

No.The roots are the complex conjugate pair 5 ± 2.4495iwhere i is the imaginary square root of -1.


What multiplies to be 8 but adds to be negative 4?

12


What multiplies to 105 and adds to 8?

113


What two numbers have a difference of 8 and a product of 30?

The complex conjugate pair, 4 ± 3.7417i where iis imaginary square root of -1.


What does 8i mean?

If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.If you mean 8i, i might be any variable, but it may also stand for the imaginary unit, sometimes defined as the square root of minus 1. In that case, 8i is 8 times the square root of minus 1.