Just add the real part and the imaginary part separately.
To form the additive inverse, negate all parts of the complex number → 8 + 3i → -8 - 3i The sum of a number and its additive inverse is 0: (8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.
x=5
15b + 13c - 12b + 10c + 8 = 3b + 23c + 8
8 of anything plus 8 more of the same thing totals up to 16 of them.
8 - 8i
(7 + 3i) + (8 + 9i) = (7 + 8) + (3i + 9i) = (7 + 8) + (3 + 9)i = 15 + 12i Which can also be written as: 15 + 12i = 3(5 + 4i).
-6i-8
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
Oh, dude, the complex conjugate of 8 + 6i is just flipping the sign of the imaginary part, so it's 8 - 6i. It's like changing your mood from happy to grumpy, but in the world of math. So yeah, that's the deal with complex conjugates.
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(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
Oh, isn't that just a happy little question? The complex conjugate of a real number like 8 is just 8 itself because there is no imaginary part to change. Just like how every tree needs its roots, every real number needs its complex conjugate to stay balanced and harmonious. Just remember, there are no mistakes, only happy little accidents in math!
No.The roots are the complex conjugate pair 5 ± 2.4495iwhere i is the imaginary square root of -1.
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The complex conjugate pair, 4 ± 3.7417i where iis imaginary square root of -1.