if you have the expression a + b*sqrt(c), the radical conjugate is a - b*sqrt(c). this is important because multiplying those two expressions together gives you an integer if a, b, and c are integers.
To eliminate the radical in the denominator.
It depends on what the denominator was to start with: a surd or irrational or a complex number. You need to find the conjugate and multiply the numerator by this conjugate as well as the denominator by the conjugate. Since multiplication is by [conjugate over conjugate], which equals 1, the value is not affected. If a and b are rational numbers, then conjugate of sqrt(b) = sqrt(b) conjugate of a + sqrt(b) = a - sqrt(b), and conjugate of a + ib = a - ib where i is the imaginary square root of -1.
its the same as itself. since there is no radical part
The concept of conjugate is usually used in complex numbers. If your complex number is a + bi, then its conjugate is a - bi.
A conjugate (in the context of math) is, simply put, two numbersseparatedby a sign, in which the sign changes.Example:The conjugate of a+b is a-b. Thepositivebecame negative.For your problem (your sign is missing, so I listed two possibilities):The conjugate of 11+17i is 11-17iThe conjugate of 11-17i is 11+17i
a+ square root of b has a conjugate a- square root of b and this is used rationalize the denominator when it contains a square root. If we want to multiply 5 x square root of 10 by something to get rid of the radical you can multiply it by square root of 10. But if we look at 5x( square root of 10 as ) 0+ 5x square root of 10 then the conjugate would be -5x square root of 10
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√a / √b = √(a/b)
The conjugate of an irrational number is a non-zero number such that the product of the two numbers is rational. In high school mathematics, you are usually required to know only the conjugates of surds of the form a + b*sqrt(x). The conjugate is a - b*sqrt(x) [-a + b*sqrt(x) is also a conjugate - all you need to do is to switch the sign of one of the two terms.]
If you mean, do you distribute a number within a radical to all the terms within the parenthesis than yes it does. Is this what you mean? radical(2)*(a+b) = radical(2)*a + radical(2)*b