Q: What is the product of the complex number a plus bi and its conjugate?

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8 - 8i

Multiply the numerator and denominator by the complex conjugate of the denominator ... [ root(2) minus i ]. This process is called 'rationalizing the denominator'.

The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)

The conjugate of 6 + i is 6 - i.

They are the complex conjugate numbers +/- 3*sqrt(2)*i where i is the imaginary square root of -1.

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The conjugate is 7-5i

The concept of conjugate is usually used in complex numbers. If your complex number is a + bi, then its conjugate is a - bi.

9-5i

To find the complex conjugate of a number, change the sign in front of the imaginary part. Thus, the complex conjugate of 14 + 12i is simply 14 - 12i.

It is 3 minus 2i

To find the complex conjugate change the sign of the imaginary part: For 11 + 5i the complex conjugate is 11 - 5i.

-5 - 7i

[ 2 - 3i ] is.

8 - 8i

3-2j.

Multiply the numerator and denominator by the complex conjugate of the denominator ... [ root(2) minus i ]. This process is called 'rationalizing the denominator'.

a-bi a(bi)-1 not negative bi