xy+3y+27
x and y are variables, so the only term that doesn't change with x or y is 27
y must be the same. so x being 6 and y being 3, 18+9 is 27.
Divide by 'x'; x2+xy/x = x(x+y)
If you mean, "x-3y = 12", then xy = 3y2 + 12y.
xy(3x - 2y)(2x + 3y)
4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)
That equals 2xy + 3y which factors to y(2x + 3)
xy + xy = 2xy
(2x - 3y)(x + y)
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
(3x+2y)*(5x-3y) =3x*5x + 3x*(-3y) + 2y*5x + 2y*(-3y) [This is sometimes called the FOIL method - You multiply the First members of each bracket, then the Outers, Inners, Lasts] = 15x2 - 9xy + 10xy - 6y2 = 15x2 + xy - 6y2
25
1,3,x,y,3x,3y,xy,3xy
It is an expression in the form of: xy+7