x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
0
4
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
If that's xy + x^2y, it factors to xy(x + 1) If it's something else, please re-submit your question with any plus signs written out.
Factor by grouping. x2y - xyb - abx + ab2 The first two can factor out an xy, so xy(x - b) The second two can factor out a -ab, so -ab(x - b) and we have xy(x - b) - ab(x - b) Since what is inside the parentheses is alike, we can be assured that we have factored correctly and now continue to group: ANS: (x - b)(xy - ab)
-16
x(y - 1)(y + 1)
The GCF is xy
2+2y+x+xy=(x+2)(y+1)
x+y
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+