2 km south
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The total displacement is 2km north, as the southward and northward displacements cancel each other out.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The resultant is 2 km South.
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
south
Indeed it is.
To find the total displacement, we calculate the net movement in the north-south direction. The child walks 4 m south and then 5 m south, totaling 9 m south. They then walk 2 m north and 5 m north, totaling 7 m north. The net displacement is 9 m south - 7 m north = 2 m south.
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.