If you mean a square with 29 feet and 9 inches sides then by using Pythagoras' theorem its diagonal is 42.073 feet rounded to 3 decimal places
A 9 x 12 rectangle has a diagonal of 15.
The diagonal of a 46' x 46' square is 65.05 feet.
Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 20 × √2 ≈ 28.3 units
By using Pythagoras: diagonal2 = side2 + side2 = side2 x 2 => diagonal = side x √2
The diagonal of a 30' x 30' square is: 42.43 feet.
If you mean a square with 29 feet and 9 inches sides then by using Pythagoras' theorem its diagonal is 42.073 feet rounded to 3 decimal places
A 9 x 12 rectangle has a diagonal of 15.
The diagonal measurement of an 18 x 18 square is: 25.46 units.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
The diagonal of a 46' x 46' square is 65.05 feet.
diagonal="c" side=9="9"="9" sincec^2=b^2+a^2, diagonal=square root of(2(9^2))=
Use Pythagoras. The diagonal, and two sides of the square form a right angled triangle. So if each side of the square is x cm long, the diagonal is x*sqrt(2) cm long.
The diagonal of a 36 x 36 foot square is 50.91 feet.
A square has 4 sides of equal length (say x). The diagonal length = x * (2)^0.5 = 1.414x, from Pythagorus's theorem. So, dividing the diagonal length by the square root of 2 will be the answer.