A 9 x 12 rectangle has a diagonal of 15.
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
116
Any rectangle that measures 12-in x 13-in has a diagonal ofsqrt(122 + 132) = 17.692 inches (rounded)
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
53.85164807' by means of Pythagoras.
The diagonal of a 12' x 24' rectangle is approx 26.8'.
32.311
150.479 units.
Yes, the diagonal of a rectangle is X.
Oh, dude, you're asking me to bust out some high school math here. So, like, to find the diagonal of a rectangle, you use the Pythagorean theorem. It's like a^2 + b^2 = c^2, where a and b are the sides of the rectangle. In this case, it's 12^2 + 16^2 = c^2. So, the diagonal would be the square root of 400, which is 20.
The diagonal is 15.652'
The diagonal is 69.856 feet.
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
116
Any rectangle that measures 12-in x 13-in has a diagonal ofsqrt(122 + 132) = 17.692 inches (rounded)
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
12 as 13 x 13 = 169 5 x 5 = 25 169 - 25 = 144 = 12 x 12