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What is the expresstion of 4 times the difference of a number an 1 is equal to 6 times the sum of a number times 3?
4*(n + 1) = 6*n*3
What is the nth term of 9 26 51 84 125?
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.
What is the difference between arithmetic progression and geometric progression?
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).
What is a number if the difference between five and twice the number is one?
5 - 2n = 1 4 = 2n n = 2
What is the difference of 8 and n?
8-n
How do you write the difference of a number and 2 is 4 as an equation?
n - 2 = 4
What is 4 times the difference of n and 8?
4n-8
What in the difference between 4-chloro-1-n-napthal and 4-chloro-1-napthal?
The main difference seen is in the extra 'n', possibly Nitrogen, in the first substance. What that change means to reactivity is outside my knowledge
Four times a number is three times the difference between thirty five and the number?
Suppose the number is N then 4N = 3*abs(35-N) where abs(35-N) is the difference between 35 and N If N > 35 then 4*N = 3*(N-35) = 3*N - 105 So N = -105 If N < 35 then 4*N = 3*(35-N) = 105 - 3*N So 7*N = 105 ie N = 15 So N = -105 or 15
What is the expresstion of 4 times the difference of a number an 1 is equal to 6 times the sum of a number times 3?
4*(n + 1) = 6*n*3
What is Three times the difference of the number and six increased by four times the number?
It is 3*abs(n - 6) + 4*n
What is the nth term for 1 5 9 13 17?
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
What is the difference of m and n?
the double of n is m. is the difference between m and n
What is the difference of a positive integer n and twice its absolute value?
Since n is positive, |n| = n, so you have 2n - n = n. The difference is n.
What is the difference of arithmetic progression to geometric progression?
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant.That is,Arithmetic progressionU(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1) + d = U(1) + (n-1)*dGeometric progressionU(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1)*r = U(1)*r^(n-1).
What is the nth term of 9 26 51 84 125?
The series is a(n) = 4n² +5n. . . and this is the general formula which also gives the nth term. When n = 1, 4n² + 5n = 4*1 + 5*1 = 9 When n = 2, 4n² + 5n = 4*4 + 5*2 = 26 . . .and so on When n = 5, 4n² + 5n = 4*25 + 5*5 = 125. The series can be determined using the Difference Technique. A second difference of 8 gives the first term 4n². . . . as a 2nd difference of 2 equates to n². After applying this to the original series, the revised series produces a 1st difference of 5, hence 5n.
What is the difference between arithmetic progression and geometric progression?
In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).
